First, let's compute the number of moles in the system assuming ideal gas behavior.

PV = nRT
(663 mmHg)(1atm/760 mmHg)(60 L) = n(0.0821 L-atm/mol-K)(20+273 K)
Solving for n,
n = 2.176 moles

At standard conditions, the standard molar volume is 22.4 L/mol. Thus,

Standard volume = 22.4 L/mol * 2.176 mol =<em> 48.74 L</em>

3 0

3 years ago

What is the volume if 1.5 mol of gas has a pressure of 700 torr at 15°C?

Tasya [4]

Answer:

V = 38.48 L

Explanation:

Given that,

No. of moles = 1.5 mol

Pressure, P = 700 torr

Temperature, T = 15°C = 288 K

We need to find the volume of the gas. The ideal gas equation is given by :

$PV=nRT\\\\V=\dfrac{nRT}{P}\\\\V=\dfrac{1.5\times 62.36\times 288}{700}\\\\V=38.48\ L$ , R = L.Torr.K⁻¹.mol⁻¹

So, the required volume is equal to 38.48 L.

7 0

2 years ago

What safety precautions are needed when running a brine electrolysis plant

nikdorinn [45]

Good ventilation as a product of it is pure Cl2 gas

4 0

2 years ago