That's easy you just need to listen in school to answer it
We have that
<span>tan(theta)sin(theta)+cos(theta)=sec(theta)
</span><span>[sin(theta)/cos(theta)] sin(theta)+cos(theta)=sec(theta)
</span>[sin²<span>(theta)/cos(theta)]+cos(theta)=sec(theta)
</span><span>the next step in this proof
is </span>write cos(theta)=cos²<span>(theta)/cos(theta) to find a common denominator
so
</span>[sin²(theta)/cos(theta)]+[cos²(theta)/cos(theta)]=sec(theta)<span>
</span>{[sin²(theta)+cos²(theta)]/cos(theta)}=sec(theta)<span>
remember that
</span>sin²(theta)+cos²(theta)=1
{[sin²(theta)+cos²(theta)]/cos(theta)}------------> 1/cos(theta)
and
1/cos(theta)=sec(theta)-------------> is ok
the answer is the option <span>B.)
He should write cos(theta)=cos^2(theta)/cos(theta) to find a common denominator.</span>
Answer:
D
Step-by-step explanation:
our basic Pythagorean identity is cos²(x) + sin²(x) = 1
we can derive the 2 other using the listed above.
1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)
1 + tan²(x) = sec²(x)
2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)
cot²(x) + 1 = csc²(x)
A. sin^2 theta -1= cos^2 theta
this is false
cos²(x) + sin²(x) = 1
isolating cos²(x)
cos²(x) = 1-sin²(x), not equal to sin²(x)-1
B. Sec^2 theta-tan^2 theta= -1
1 + tan²(x) = sec²(x)
sec²(x)-tan(x) = 1, not -1
false
C. -cos^2 theta-1= sin^2
cos²(x) + sin²(x) = 1
sin²(x) = 1-cos²(x), our 1 is positive not negative, so false
D. Cot^2 theta - csc^2 theta=-1
cot²(x) + 1 = csc²(x)
isolating 1
1 = csc²(x) - cot²(x)
multiplying both sides by -1
-1 = cot²(x) - csc²(x)
TRUE
Step-by-step explanation:
Slope=9
i)
When line is parallel
y+5=9(x-6)
y+5 = 9x - 54
<h3>59 = 9x-y </h3>
When line is perpendicular
y+5=-1/9(x-6)
9(y+5)= -1(x-6)
9y + 45 = -x+6
<h3>
x+9y = -39</h3>
<h2>
MARK ME AS BRAINLIST </h2>
The value of the composite function f(g(x)) is 2x^2 + 15
<h3>How to evaluate the composite function f(g(x))?</h3>
The functions are given as:
f(x) = 2x + 1
g(x) = x^2 + 7
We have the function f(x) to be
f(x) = 2x + 1
Substitute g(x) for x in the equation f(x) = 2x + 1
So, we have
f(g(x)) = 2g(x) + 1
Substitute g(x) = x^2 + 7 in the equation f(g(x)) = 2x + 1
f(g(x)) = 2(x^2 + 7) + 1
Open the brackets
f(g(x)) = 2x^2 + 14 + 1
Evaluate the sum
f(g(x)) = 2x^2 + 15
Hence, the value of the composite function f(g(x)) is 2x^2 + 15
Read more about composite function at
brainly.com/question/10687170
#SPJ1
<u>Complete question</u>
if f(x) = 2x + 1 and g(x) = x^2 + 7
which of the following is equal to f(g(x))