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The present age of Jane is 45 years old and present age of her sister is 9 years old
<em><u>Solution:</u></em>
Let the present age of Jane be "x"
Let the present age of her sister be "y"
<em><u>Jane is 5 times older than her sister</u></em>
present age of Jane = 5(present age of her sister)
x = 5y ---------- eqn 1
<em><u>In 3 years, Jane’s sister will be 1/4 her age</u></em>
Age of sister after 3 years = 3 + y
Age of jane after 3 years = 3 + x
Age of sister after 3 years = 1/4(age of jane after 3 years)
Substitute eqn 1 in above equation
Substitute y = 9 in eqn 1
x = 5(9)
x = 45
Thus present age of Jane is 45 years old and present age of her sister is 9 years old
<span>The table must show:
Time (minutes) number of gallons remaining
X y
0 Yo
1 Yo – 1.5
2 Yo – 2*1.5
3 Yo – 3*1.5
4 Yo – 4*1.5
And the equation will be ; Y = Yo – 1.5 x, where Yo is the initial amount of water in the bathtub.</span>
Answer:
6(8w + 7x)
Step-by-step explanation:
Hello!
The greatest common factor between 48 and 42 is 6. We can factor out 6 from each term.
<h3>Factor</h3>
- 48w + 42x
- 6(8w) + 6(7x)
- 6(8w + 7x)
The expression is 6(8w + 7x).
The answer is seven. Fifty-six divided by eight is seven.