X^2+y^2 = 16
can be written as
(x-0)^2+(y-0)^2 = 4^2
We see that the second equation is in the form
(x-h)^2 + (y-k)^2 = r^2
where
(h,k) = (0,0) is the center
r = 4 is the radius
The polar form of the equation is simply r = 4. Why is this? Because the radius is fixed to be 4 no matter what happens with theta. As theta goes from 0 to 360, the points generated all form a circle centered at (0,0) with radius 4.
Answer: r = 4
Answer:
t=1/30 h = 2 min
Step-by-step explanation:
d = vt
system of equations:
d = 13t
d - 2/5 = t -> d = t+2/5
Solve
13t = t +2/5
t = 1/30 h = 60 min / 30 = 2 min
Answer:
5
Step-by-step explanation:
When squaring the number 5 (i.e 
) the answer is 25. 
is the same thing as 5 times 5. Basically with the square root, you are going backwards, so you are therefore finding the base of it all.
