All categories

2 years ago

What type of sound is produced when string vibrates rapidly?

Physics

1 answer:

amid [387]2 years ago

8 0

The faster a string vibrates, the higher frequency sound it produces,
and the higher the pitch is that we hear.

You might be interested in

Mountain Ecosystems Assignment Answer each question below in complete sentences.1) Identify a predator from an Ethiopian Highlan

Marta_Voda [28]

An example of a a predator in the Ethiopian Highlands ecosystem is the

Wolf.The wolf is a carnivore which acts as a predator to other smaller

animals in the ecosystem.

Preys are mostly smaller animals in which the predators feed on for food.

They are usually herbivores and primary consumers in the ecosystem.

Examples of Preys include:

Rodents

Deer

Bison etc.

Read more about Feeding relationship here brainly.com/question/9852437

8 0

1 year ago

Using the videos and websites provided, or other online resources you find, and analyze the events of the Biosphere 2 story and

Andru [333]

Your answer has to be B

4 0

2 years ago

Read 2 more answers

A long, thin rod parallel to the y-axis is located at x = - 1 cm and carries a uniform positive charge density λ = 1 nC/m . A se

zheka24 [161]

Answer:

The electric field at origin is 3600 N/C

Solution:

As per the question:

Charge density of rod 1, $\lambda = 1\ nC = 1\times 10^{- 9}\ C$

Charge density of rod 2, $\lambda = - 1\ nC = - 1\times 10^{- 9}\ C$

Now,

To calculate the electric field at origin:

We know that the electric field due to a long rod is given by:

$\vec{E} = \frac{\lambda }{2\pi \epsilon_{o}{R}$

Also,

$\vec{E} = \frac{2K\lambda }{R}$ (1)

where

K = electrostatic constant = $\frac{1}{4\pi \epsilon_{o} R}$

R = Distance

$\lambda$ = linear charge density

Now,

In case, the charge is positive, the electric field is away from the rod and towards it if the charge is negative.

At x = - 1 cm = - 0.01 m:

Using eqn (1):

$\vec{E} = \frac{2\times 9\times 10^{9}\times 1\times 10^{- 9}}{0.01} = 1800\ N/C$

$\vec{E} = 1800\ N/C$ (towards)

Now, at x = 1 cm = 0.01 m :

Using eqn (1):

$\vec{E'} = \frac{2\times 9\times 10^{9}\times - 1\times 10^{- 9}}{0.01} = - 1800\ N/C$

$\vec{E'} = 1800\ N/C$ (towards)

Now, the total field at the origin is the sum of both the fields:

$\vec{E_{net}} = 1800 + 1800 = 3600\ N/C$

7 0

2 years ago

The mass of a triton is

Margarita [4]

2.14x 1022 kg

the 22 is a xponet of ten

7 0

2 years ago

Read 2 more answers

A 12 kg barrel is pulled up by a rope. The barrel accelerates at 1.2 m/s2. Find the force exerted by the rope. Show all your wor

IgorLugansk [536]

Answer:

F = 132N

Explanation:

Let the pulling force be F

Given the mass of the barrel is 12 Kg and The acceleration is 1.2 m/ $sec^2$

We know that Net Force = $mass\times acceleration$

Now net force = F - mg

F - mg = ma

F = mg + ma

F = m(a+g) = $12\times (1.2 +9.8)=132N$

Note that there will be a downward force acting on the body which is equal to mg

3 0

2 years ago