The range is 327 the maxim subtract the minimum
The velocity of the particle is given by
Since 
and 
, we get
Similarly, the position function is obtained via
We know 
and we're told that 
, so
making the answer A.
Answer:
The proof is below
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of a parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of a parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
97
Explanation:
487/5=97
Answer:
-32p+56
Step-by-step explanation:
-8*4p=-32p
-7*-8=56(negative times negative =positive)
-32p+56
