Question: A car (assumed to be a Ford Taurus) is traveling around a turn that is banked at 7 degrees. The turn has a radius of 2
9 m. The car has a mass of 1300 kg. The coefficient of static friction between the tires and the road is 0.68.
1. What is the "ideal speed?" That is, what speed would allow the car to make the turn without requiring friction?
2. What is the maximum speed the car can go around the turn without sliding?
1. What is the "ideal speed?" That is, what speed would allow the car to make the turn without requiring friction?
2. What is the maximum speed the car can go around the turn without sliding?
1 answer:
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Answer:
3.7 m/s^2
Explanation:
The period of a simple pendulum is given by:
where L is the length of the pendulum and g is the free-fall acceleration on the planet.
Calling L the length of the pendulum, we know that:
is the period of the pendulum on Earth, and
is the free-fall acceleration on Earth
is the period of the pendulum on Mars, and
is the free-fall acceleration on Mars
Dividing the two expressions we get
And re-arranging it we can find the value of the free-fall acceleration on Mars: