The preimeter of a rectangle is equal to 2 times the length plus twice the width
2 answers:
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The picture in the attached figure
we know that
perimeter of a rectangle=2*[base+height]
base=3y+1
height=2y+3
perimeter=90 units
so
90=2*[(3y+1)+(2y+3)]-----> 90=2*[5y+4]----> 10y+8=90----> y=8.2 units
base=3y+1-----> base=3*8.2+1-----> 25.6 units
height=2y+3----> height= 2*8.2+3---> 19.4 units
the answer is
<span>the length of side vy is (2y+3)-----> 19.4 units</span>
we know that
perimeter of a rectangle=2*[base+height]
base=3y+1
height=2y+3
perimeter=90 units
so
90=2*[(3y+1)+(2y+3)]-----> 90=2*[5y+4]----> 10y+8=90----> y=8.2 units
base=3y+1-----> base=3*8.2+1-----> 25.6 units
height=2y+3----> height= 2*8.2+3---> 19.4 units
the answer is
<span>the length of side vy is (2y+3)-----> 19.4 units</span>
Answer:
d=1
Step-by-step explanation:
Lets factor the denominator d^2 -2d-8
d^2 - 2d - 8 = (d-4)(d+2)
Now make the denominators same
LCD: (d-4)(d+2)
Denominators are same on both sides
So equate the numerators
-3d +3(d+2) = -2(d-4)
-3d +3d +6 = -2d +8
6 = -2d + 8
subtract 8 on both sides
-2 = -2d
So d=1