The equation that we can create from this situation is:
i = (190 – 5 x) * (29 + x)
where i is the income and x is the increase in daily rate
Expanding the equation:
i = 5510 + 190x – 145x - 5x^2
i = -5x^2 + 45x + 5510
Taking the 1st derivative:
di/dx = -10x +45
Set to zero to get the maxima:
-10x + 45 = 0
x = 4.5
So the cars should be rented at:
29 + x = 33.5 dollars per day
The maximum income is:
i = (190 – 5*4.5) * (33.5)
i = 5,611.25 dollars
Answer:
C
Step-by-step explanation:
Answer = 0
n can have possible values from (-12) to 12
-12 <= n < 12
(-12) + (-11)+(-10)......+10+11+12=0
Answer:
8.0
Step-by-step explanation:
