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2 years ago

3 (x- 4) = 2 (x+1) Justification reason

Mathematics

1 answer:

Murrr4er [49]2 years ago

5 0

Solution

=14

Step-by-step explanation:

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nayeli is a real estate agent. she earns 7.5% commission on each sale she makes. last month she sold two houses. one for $175,00

NNADVOKAT [17]

Answer:

she earned $288.75 in commissions

Step-by-step explanation:

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3 years ago

Find the measure of angle A

Gre4nikov [31]

Answer:

21 degrees

Step-by-step explanation:

Triangles have a total angle of 180 degrees.

This makes our equation:

3x+3+4x+135=180

Subtract 135 from both sides and combine like terms

7x + 3 = 45

Subtract 3 from both sides

7x = 42

Divide both sides by 7

x = 6

Plugging the number in:

3x + 3 =

3(6) + 3 =

7 0

2 years ago

TRUE or FALSE. In a randomly generated list of numbers from 0 to 5, the chance that each number can occur is 1/5 .

mel-nik [20]

Thank you for posting your question here at brainly. Feel free to ask more questions.

<span>The best and most correct answer among the choices provided by the question is FALSE.</span><span>
</span><span>
<span>Hope my answer would be a great help for you.</span></span>

3 0

2 years ago

Read 2 more answers

Log(x-2)+log2=2logy<br>log(x-3y+3)=0

In-s [12.5K]

Answer:

Step-by-step explanation:

$\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right$

$===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}$

$\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac$

$y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D$

$\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D$

4 0

2 years ago

Question 20 fast please

kipiarov [429]

Answer:

Square root of 4 is 2

so 1+ $\frac{[1+\sqrt{2x-1]}^2 }{4}$ =4

frac{[1+sqrt{2x-1]}^2 }{4}=3

so 1+sqrt{2x-1]}^2=12

so 1+sqrt{2x-1}=V12

sqrt{2x-1}=V12-1

2x-1=(V12-1)^2=12-2V12+1=13-2V12

2x=13+1-2V12

2x=14-2V12

x=7-V12

x=7-2V3

I put an attachment to explain better

Step-by-step explanation:

6 0

2 years ago