The change of base formula looks like this:
log x
(log to the base b of ) x = ----------- (you could also use ln instead of log)
log b
log 40 1.602
Then (log to the base 7 of) 40 = ------------ = ------------- = 1.896 (answer)
log 7 0.8451
check (on calculator): 7^1.896 = 40.023 (close enough to 40 to verify
that this method "worked")
<h2>
<em>Answer:</em></h2><h2>
<em>1</em><em>3</em><em>1</em><em>.</em><em>9</em><em>6</em><em>4</em><em> </em><em>cm</em></h2>
<em>Solution,</em>
<em>radius=</em><em>2</em><em>1</em><em> </em><em>cm</em>
<em>Circumference</em><em> </em><em>of </em><em>circle</em><em>=</em><em>2</em><em> </em><em>pi </em><em>r</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>*</em><em>3</em><em>.</em><em>1</em><em>4</em><em>2</em><em>*</em><em>2</em><em>1</em>
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>1</em><em>3</em><em>1</em><em>.</em><em>9</em><em>6</em><em>4</em><em> </em><em>cm</em>
<em>hope </em><em>it</em><em> helps</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
The half life of a decaying substance is defined as the time at which the substance decreases to one-half of its original value. In this case, given hlf-life of 10 years and an original mass of 50 grams, after 10 years, the isotope mass becomes 50*0.5 or 25 grams. Answer is B.
Answer: the dwarf tree grew by 3 inches.
the semi dwarf tree grew by 6 inches.
the full size tree grew by 18 inches.
Step-by-step explanation:
Let x represent how much the semi-dwarf lemon tree grew.
Last month, a dwarf lemon tree grew half as much as a semi-dwarf lemon tree. This means that the amount by which the dwarf lemon tree grew is expressed as x/2
A full-size lemon tree grew three times as much as the semi-dwarf lemon. This means that the amount by which the full-size lemon tree grew is expressed as 3x
Together, the three trees grew 27 inches. This means that
x/2 + x + 3x = 27
Cross multiplying by 2, it becomes
x + 2x + 6x = 54
9x = 54
x = 54/9
x = 6 inches
The dwarf tree grew by 6/2 = 3 inches.
The full-size lemon tree grew by 3 × 6 = 18 inches
this one lol
Step-by-step explanation:
because this shape has 12 sides when every other shape has 13