What is an equation for the line perpendicular to y=-1/8x+6 that passes through (-3,-10)
1 answer:
Answer:
y = 8x + 14
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = - x + 6 ← is in slope- intercept form
with slope m = -
Given a line with slope m then the slope of a line perpendicular to it is
= -
= -
= 8 , then
y = 8x + c ← is the partial equation
To find c substitute (- 3, - 10 ) into the partial equation
- 10 = - 24 + c ⇒ c = - 10 + 24 = 14
y = 8x + 14 ← equation of perpendicular line
You might be interested in
Answer:
Step-by-step explanation:
I'm assuming you meant to type in
because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to
and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.
The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!