The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:
<span><span>x1 </span>= 0.42801</span>
<span><span>x2 </span>= −1.51414</span>
<span><span>x3 </span>= 3.08613</span>
x1 and x2 are in the desired interval [-2, 2]
f'(x) = 3x^2 - 4x - 4
so we have:
3x^2 - 4x - 4 = 0
<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6
x_1 = -4/6 = -0.66
x_ 2 = 2
According to Rolle's theorem, we have one point in between:
x1 = 0.42801 and x2 = −1.51414
where f'(x) = 0, and that is <span>x_1 = -0.66</span>
so we see that Rolle's theorem holds in our function.
Answer: The vertex of the parabola (quadratic function) is (-2,-4)
Fourth option: (-2,-4)
Solution:
y=x^2+4x
y=ax^2+bx+c; a=1, b=4, c=0
Vertex: V=(h,k)
h=-b/(2a)
h=-4/(2(1))
h=-4/2
h=-2
y=x^2+4x
k=y=h^2+4h
k=(-2)^2+4(-2)
k=4-8
k=-4
Vertex: V=(h,k)
Vertex: V=( -2, -4)
Answer:
U shaped.
Step-by-step explanation:
When x = 0 , f(x) = 6
when x =1 yf(x) = 0
when x = 2 f(x) = -2
x = 3 f(x) = 0
x = 4 f(x) = 6.
So the graphs falls from the left and rises to the right in the form of a U.
You can draw a rough graph to confirm this.
Answer:
see below
Step-by-step explanation:
The graph of it on a number line is an open circle at x=3 with a line extending to the right through larger numbers.
When the inequality does not include the "or equal to" case, the boundary is graphed as a dashed line (on an x-y plane) or open circle (on a number line). The shaded area covers values of the variable that meet the condition of the inequality. Here, those are values of x that are more than 3.
I'm pretty sure you just multiply the 1 1/4 by 3 because if 1 1/4 makes 10 muffins you need to make 3 more dozens so 1 1/4 times 3 equals 3.75