The observer can conclude that the sound is moving away from them and that its speed is increasing.
My inference is that the water molecules are moving up and down. I don't know for sure but i'm usually correct.
Answer:
(a): the mug hits the floor 0.752m away from the end of the bar.
(b): the speed of the mug at impact are:
V= 4.87 m/s
direction= 70.82º below the horizontal.
Explanation:
Vx= 1.6 m/s
Vy=?
h= 1.1 m
g= 9.8 m/s²
t is the fall time
t=0.47 sec
Vy= g*t
Vy= 4.6 m/s
V= 4.87 m/s
α= tan⁻¹(Vy/Vx)
α= -70.82º