Answer:
I honestly do not know im sorry something else?
Step-by-step explanation:
Reorder from least to greatest.
4, 4, 6, 6, 6, 8, 10, 15, 15
/\
|
Median is the middle number.
This would be 6.
---
hope it helps
Answer:
x=-2 x=1
Step-by-step explanation:
16x2 + 10x – 27 = -6x + 5
Add 6x to each side
16x^2+6x + 10x – 27 = -6x+6x + 5
16x^2 +16x -27 = 5
Subtract 5 from each side
16x^2 + 16x – 27-5 = 5 - 5
16x^2 +16x -32 = 0
Factor out 16
16 (x^2 +x-2)=0
Factor
16 (x+2) (x-1) =0
Using the zero product property
(x+2) =0 x-1=0
x=-2 x=1
Answer:
- The shaded region is 9.83 cm²
Step-by-step explanation:
<em>Refer to attached diagram with added details.</em>
<h2>Given </h2>
Circle O with:
- OA = OB = OD - radius
- OC = OD = 2 cm
<h2>To find</h2>
<h2>Solution</h2>
Since r = OC + CD, the radius is 4 cm.
Consider right triangles OAC or OBC:
- They have one leg of 2 cm and hypotenuse of 4 cm, so the hypotenuse is twice the short leg.
Recall the property of 30°x60°x90° triangle:
- a : b : c = 1 : √3 : 2, where a- short leg, b- long leg, c- hypotenuse.
It means OC: OA = 1 : 2, so angles AOC and BOC are both 60° as adjacent to short legs.
In order to find the shaded area we need to find the area of sector OADB and subtract the area of triangle OAB.
Area of <u>sector:</u>
- A = π(θ/360)r², where θ- central angle,
- A = π*((mAOC + mBOC)/360)*r²,
- A = π*((60 + 60)/360))(4²) = 16.76 cm².
Area of<u> triangle AO</u>B:
- A = (1/2)*OC*(AC + BC), AC = BC = OC√3 according to the property of 30x60x90 triangle.
- A = (1/2)(2*2√3)*2 = 4√3 = 6.93 cm²
The shaded area is:
- A = 16.76 - 6.93 = 9.83 cm²
Yesyesyes thank you have an amazing day!