Answer:
x=y^2-2
Step-by-step explanation:
This graph, is a parabola that opens to the right.
To answer this question, we just use the vertex form of a sideways parabola- x=a(y-k)^2+h.
In this case, the vertex is (-2, 0), and our value of a is 1, since it opens to the right.
This gives us: x=1(y-0)^2+(-2)
Which simplifies to: x=y^2-2.
Also, the answer to the previous two questions are wrong.
The D value (Domain) is actually [2, ∞)
The R value (Range) is actually "All real numbers" (-∞, ∞)
Let me know if this helps!
Y= 2x-1
Explanation: First, you find slope. If the first point it x-axis point is 0 and the second x-axis point is 1 then you already know the answer is over 1, so you have to figure out how many up you are going on the y-axis from -1 to 1. Which is 2, so your slope is 2/1 or just 2. Next, you find your y-intercept, which is where the line crosses the y-axis, and the easy way to find this is finding what y is equal to when x is equal to 0, in the problem you are told (0, -1) as a point, so they gave you your y-intercept right there, which is -1. Finally you right the equation in slip intercept form (y= mx+b) which is y= 2x-1
Answer: i havent done this in a long long time but i think it may be
15n-0.10
Step-by-step explanation: