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1 year ago

Jake lifted a 10-kg bell by a distance of 0.50 meters in 0.50 seconds. How much power did Jake use?

Physics

1 answer:

Reil [10]1 year ago

8 0

Answer:

10 watts

Explanation:

first calculate work.

Work =force×distance cos thita

10Kg×0.50M cos 0= 5joules

Therefore, Power=Work÷ Time

Therefore, 5joules÷0.50s=10 watts.

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10. A force F S 1 of magnitude 6.00 units acts on an object at the ori- gin in a direction u 5 30.0° above the positive x axis (

MArishka [77]

Answer:

The x component of the x axis is: $F_x = F_1\cos(30)=5\cos(30)= 4.33 u$

The y component of the y axis is: $F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u$

The magnitude is given by: $F = \sqrt{F_x+F_y}= 9.54 u$

The direction is given by: $\theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ$

See the graphical magnitude and direction below.

Explanation:

The x component of the x axis is: $F_x = F_1\cos(30)=5\cos(30)= 4.33 u$

The y component of the y axis is: $F_y =F_2+ F_1\sin(30)=6.00+5\sin(30)= 8.50 u$

The magnitude is given by: $F = \sqrt{F_x+F_y}= 9.54 u$

The direction is given by: $\theta = \tan^{-1}\frac{F_y}{F_x}= 63.0 ^\circ$

8 0

2 years ago

A crate pushed along the floor with velocity vâ i slides a distance d after the pushing force is removed. if the mass of the cra

Alenkinab [10]

<span>d The mass is doubled which means that both the momentum and kinetic energy are also doubled. Also the normal force that's acting along with the coefficient of kinetic friction is also doubled. So the friction that's working to slow down the crate is doubled. So the crate will have double the kinetic energy that needs to be dissipated, but the rate of dissipation is also doubled, so the total time required to dissipate the kinetic energy is the same. And since both crates start out with the same velocity and since they'll lose energy (and velocity) at the same proportional rate, they'll take the same distance to slide to a stop.</span>

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3 years ago

In which electric circuit would the voltmeter read 10 volts ?

ki77a [65]

Given that,

Voltage = 10 volt

Suppose, The three resistance is connected in parallel and each resistance is 12 Ω. find the current in the electric circuit.

We need to calculate the equivalent resistance

Using formula of parallel

$\dfrac{1}{R}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}+\dfrac{1}{R_{3}}$

Put the value into the formula

$\dfrac{1}{R}=\dfrac{1}{12}+\dfrac{1}{12}+\dfrac{1}{12}$

$\dfrac{1}{R}=\dfrac{1}{4}$

$R=4\ \Omega$

We need to calculate the current in the circuit

Using ohm's law

$V=IR$

$I=\dfrac{V}{R}$

Where, V = voltage

R = resistance

Put the value into the formula

$I=\dfrac{10}{4}$

$I=2.5\ A$

Hence, The current in the circuit is 2.5 A

4 0

2 years ago

The parietal lobe is the portion of the cerebral cortex located below the temporal lobe.

jasenka [17]

Answer:

False

Explanation:

Please see the attached file

5 0

2 years ago

Read 2 more answers

1 point

Trava [24]

Answer:

Their number should increase

Explanation:

The photoelectric effect is a phenomenon that causes the ejection of electrons from that metal as light shined onto a metal surface. Only certain frequencies of light can cause the ejection of electrons. However, if the frequency of the incident light is too low then no electrons were ejected even if the intensity of the light was very high. If the frequency of the light was higher then electrons were able to be ejected from the metal surface even if the intensity of the light was very low.

According to the accepted wave theory, light of any frequency will cause electrons to be emitted. Kinetic energy emitted by the electrons depends upon the intensity of light.

According to the accepted wave theory, number of electrons being ejected by the metal should increase

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2 years ago

Jake lifted a 10-kg bell by a distance of 0.50 meters in 0.50 seconds. How much power did Jake use?​

Jake lifted a 10-kg bell by a distance of 0.50 meters in 0.50 seconds. How much power did Jake use?