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1 year ago

Need help solving this problem please

Mathematics

1 answer:

jeyben [28]1 year ago

5 0

very simple very simple and it is very good for your health and all things

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Quadrilateral JKLM is graphed with vertices at J(-2,2), K(-1,-5), L(4,0), and M(3,7).

AveGali [126]

Answer:

<u>Question (a)</u>

Midpoint of a line segment:

$M=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Given:

J = (-2, 2)
L = (4, 0)

$\implies \textsf{midpoint of }JL=\left(\dfrac{-2+4}{2},\dfrac{2+0}{2}\right)=(1,1)$

Given:

M = (3, 7)
K = (-1, -5)

$\implies \textsf{midpoint of }MK=\left(\dfrac{3-1}{2},\dfrac{7-5}{2}\right)=(1, 1)$

<u>Question (b)</u>

Find slopes (gradients) of JL and MK then compare. If the product of the slopes of JL and MK equal -1, then JL and MK are perpendicular.

$\textsf{slope }m=\dfrac{y_2-y_1}{x_2-x_1}$

Given:

J = (-2, 2)
L = (4, 0)

$\implies \textsf{slope of }JL=\dfrac{0-2}{4+2}=-\dfrac13$

Given:

M = (3, 7)
K = (-1, -5)

$\implies \textsf{slope of }MK=\dfrac{-5-7}{-1-3}=3$

$\textsf{slope of }JL \times \textsf{slope of }MK=-\dfrac13 \times3=-1$

Hence segments JL and MK are perpendicular

4 0

1 year ago

6 high school seniors choose from among 20 quotes for their yearbook. What is the probability that at least 2 of them choose the

shusha [124]

Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

In this problem, we have that:

There are 6 students, hence n = 6.

There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

$P(X \geq 2) = 1 - P(X < 2)$

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351$

$P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321$

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328$

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

6 0

1 year ago

X+5-8x=26<br> Solve for x

salantis [7]

X = -3

Pull out the like terms: -7x - 21 = -7 × ( x + 3)

Solve: -7 = 0

Solve: x + 3 = 0

Subtract 3 from both sides of the equation

So, x = -3

5 0

2 years ago

Read 2 more answers

In a bag of marbles you have three green, two yellow, six blue, and nine red marbles. What is the probability of picking a red m

guajiro [1.7K]

$|\Omega|=3+2+6+9=20-a\ number\ of\ all\ marables\\\\|R|=9-a\ number\ of\ red\ marables\\\\\boxed{P(R)=\dfrac{9}{20}}$

3 0

2 years ago

How do I solve this quadratic equations by factoring

Aleks [24]

If xy=0, assume that x and/or y=0

so we already gots factored
therfor
assume
3n-2=0 and 4n+1=0
solve

3n-2=0
3n=2
n=2/3

4n+1=0
4n=-1
n=-1/4

n=2/3 and/or -1/4

7 0

3 years ago