Using conditional probability, it is found that there is a 0.2273 = 22.73% probability that a student took AP Chemistry, given they did not get into their first-choice college.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
- is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Did not get into their first-choice college.
- Event B: Took AP chemistry.
According to the chain given, the percentages associated with not getting into their first-choice college are:
Hence:
The probability of both not getting into their first-choice college and taking chemistry is 0.1375, hence
Then, the conditional probability is:
0.2273 = 22.73% probability that a student took AP Chemistry, given they did not get into their first-choice college.
To learn more about conditional probability, you can take a look at brainly.com/question/14398287
Answer:
5.6<x<∞
Step-by-step explanation:
x has to be no less than or equal to 2.8+2.8. So, x>5.6
x is less than∞
Answer:
C). 0.83193
Step-by-step explanation:
There are total of 90 passengers of which 27 are for business.
The probability of passengers for business = 27/90
The probability of passengers for business p = 0.3
The probability of passengers not for business q = 1-The probability of passengers for business
= 1-0.3
= 0.7
Random sample of 5 passenger, probability of at least one business passenger = 1 - probability of no business passenger
probability of no business passenger
= 5C0(0.3)^0 * (0.7)^5
= 1 *1*0.16807
= 0.16807
probability of at least one business passenger = 1 - probability of no business passenger
= 1-0.16807
=0.83193
What is the range of the data set? {43.2, 46.8, 44.5, 46.8, 44.2, 41.9, 45.8, 46.9, 41.2, 46.8, 44.1}
lilavasa [31]
Answer:
the range of this answer is 5.6
Answer:
Step-by-step explanation:
Given
Required
The total price for 5 days
First, calculate the total for a day.
Open bracket
For 5 days, the total will be.
Total = days * sales of a day
So, we have: