i feel your pain though :/
Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>
Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get
Hence amount owed at the end of 1 year is 3640
Answer:
Expanded:x²-7x+4x-28
Simplified: x²-3x-28
Step-by-step explanation:
Answer:
FV= $634.12
Step-by-step explanation:
Giving the following formula:
Initial investment (PV)= $500
Number of periods (n)= 3*4= 12 quarters
Interest rate (i)= 0.08/4= 0.02
<u>To calculate the future value, we need to use the following formula:</u>
<u></u>
FV= PV* (1 + i)^n
FV= 500*(1.02^12)
FV= $634.12
Answer:
C
Step-by-step explanation:
We can use process of elimination
D is incorrect because the roots are 3 and -4 and there are no negative roots visible
B is wrong because the roots -3 and -6 are both negative
You can factor A into (x-2)(x-3) and the roots are 2 and 3 but the roots on the graph look closer to 3 and 6
For C it can be factored as (x-6)(x-3) so the roots are 3 and 6 which look accurate