Answer:
2z(4z^2+1)(2z+1)(2z-1)
Step-by-step explanation:
here is just some basic polynomial factoring where you find something both the numbers have in common and you take that out of the equation. here i just went a little bit deeper and after taking out the common factor i also expanded my answer further as this would be the fully correct answer.
hope this helps!
Answer:
are there options if there are i can help
Step-by-step explanation:
Answer:
The ordered pair is (1, 2) ⇒ A
Step-by-step explanation:
In the function f(x) = y
- x is the domain of the function
- y is the range of the function
- The domain is all the x-coordinates of the points lie on the graph of the function
- The range is all the y-coordinates of the points lie on the graph of the function
That means any ordered pair (x, y) satisfy the function f(x) = y, lies on the graph of the function
∵ f(x) = 2x
→ That means y = 2x
∵ x = 1
→ Substitute the value of x in the function above
∴ f(1) = 2(1)
∴ f(1) = 2
→ That means at x = 1, y = 2
∴ The ordered pair is (1, 2)
