Answer:
The sample size required is, <em>n</em> = 502.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion is:
The margin of error is:
Assume that 50% of the people would support this political candidate.
The margin of error is, MOE = 0.05.
The critical value of <em>z</em> for 97.5% confidence level is:
<em>z</em> = 2.24
Compute the sample size as follows:
![n=[\frac{z_{\alpha/2}\times \sqrt{\hat p(1-\hat p)}}{MOE}]^{2}](https://tex.z-dn.net/?f=n%3D%5B%5Cfrac%7Bz_%7B%5Calpha%2F2%7D%5Ctimes%20%5Csqrt%7B%5Chat%20p%281-%5Chat%20p%29%7D%7D%7BMOE%7D%5D%5E%7B2%7D)
![=[\frac{2.24\times \sqrt{0.50(1-0.50)}}{0.05}]^{2}\\\\=501.76\\\\\approx 502](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B2.24%5Ctimes%20%5Csqrt%7B0.50%281-0.50%29%7D%7D%7B0.05%7D%5D%5E%7B2%7D%5C%5C%5C%5C%3D501.76%5C%5C%5C%5C%5Capprox%20502)
Thus, the sample size required is, <em>n</em> = 502.
X+y+z=51
y=2z
z=9+x
subsitute those
x+2z+9+x=51
x+2(9+x)+9+x=51
x+18+2x+9+x=51
4x+27=51
minus 27 both sides
4x=24
divide by 4
x=6
sub back
z=9+x
z=9+6
z=15
y=2z
y=2(15)
y=30
the numbers are
6,30,15
Answer:
line 2
Step-by-step explanation:
on line 2 the two minuses at the end turn into a + (where the -2 is there should be a +2) because - x - = +
First, put the numbers in order
A. 1,2,3,4,5,7,8,8,9.....median (middle number) is 5..when there is an odd number of data values, there will only be one median.
B. 14,14,15,16,17,18,19,20....if there is an even number of data points, there will be 2 middle numbers. In that case, u add the 2 middle numbers and divide by 2 to find the median. (16 + 17) / 2 = 33/2 = 16.5 is ur median.
Answer:
1/7
Step-by-step explanation:
There are 52 weeks in a year. Each have one Monday. Leap years have a total of 366 days. There are 7 days of the week. Monday is one of them, so it'll be a 1/7 chance.
