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Answer:
(x, y) = (-6, 15) and (2, -1)
Step-by-step explanation:
You can start by subtracting the second equation from the first.
(y) -(y) = (x^2 +2x -9) -(-2x +3)
0 = x^2 +4x -12 . . . . . . collect terms
0 = (x +6)(x -2) . . . . . . . factor
Solutions for x are -6 and +2. These values make the factors zero.
The corresponding solutions for y are ...
y = -2(-6) +3 = 15
y = -2(2) +3 = -1
Solutions to the system of equations are ...
(x, y) = (-6, 15) and (2, -1)
I wanna say it is 49 I answered on my calculator!
Answer:
Step-by-step explanation:
(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab² + 3cb² +3 ac² + 3bc² + 6abc
a = 5a ; b =y ; c = z
(5x + y + z)(5z + y + z )(5z + y +z) = (5x + y +z)³
= (5x)³ + y³ +z³ + 3(5x)²y + 3(5x)²z + 3(5x)*y² + 3*z*y² + 3*5x*z² + 3*y*z² + 6*5x*y*z
= 125x³ + y³ +z³ + 3*25x²y + 3*25x²*z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz
= 125x³ + y³ + z³ + 75x²y + 75x²z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz
Answer:
Step-by-step explanation:
9kg