The easiest way to attempt such questions is to throw in some numbers and do trial and error.
The question is asking about the change in values
depending on the change in
. So, let's play around with
.
Take
, then
Take
, then
Take
, then
.
.
.
Take
, then
Notice how
decreases in value for every increase in
?
Therefore, as
increases, the value of
decreases (always).
Ans: B
Answer:
yes you are right
Step-by-step explanation:
Answer:
h(x) = 11/(x -4)
Step-by-step explanation:
The domain of m(x) is restricted to x≠1. That means the domain of m(n(x)) must be restricted so that n(x)≠1, or x≠4.
The only offered choice with a domain restriction x≠4 is the 3rd choice:
h(x) = 11/(x -4)
Answer:
b
Step-by-step explanation:
Answer:
Step-by-step explanation:
A particle is moving with acceleration modeled by the function:
We are given that its position s(t) at <em>t</em> = 0 is 10 and that its velocity v(t) at <em>t</em> = 0 is 16.
And we want to find its position at <em>t</em> = 8.
Velocity is the integral of the acceleration. Hence:
Find the velocity. Remember the constant of integration!
Since v(t) is 16 when <em>t</em> = 0:
Hence, our velocity is given by:
Position is the integral of the velocity. Hence:
Integrate:
s(t) is 10 when <em>t</em> = 10. Hence:
So, our position function is:
The position at <em>t</em> = 8 will be:
