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1 year ago

9

What is the domain of the relation graphed below?

1 answer:

grin007 [14]1 year ago

6 0

Answer:

A

Step-by-step explanation:

I took it

You might be interested in

Simplify by combining like terms on each side of the equation. State your new equation.

vladimir1956 [14]

6x + x + x - 5 - 2 = 8 + 2x + x

combine like terms

8x -7 = 8 +3x

subtract 3x from each side

5x -7 = 8

add 7 to each side

5x = 15

divide by 5

x=3

Answer: 8x -7 = 8 +3x

x=3

6 0

2 years ago

I NEED HELP LIKE RIGHT NOW!!

Bess [88]

Answer:

The answer in the attached figure

Step-by-step explanation:

Let

x------> the abscissa

y-----> the ordinate

we know that

$y=2x$ -----> given problem

The domain is $[-1, 0, 1]$

so

For $x=-1$

$y=2(-1)=-2$

The point is $(-1,-2)$

For $x=0$

$y=2(0)=0$

The point is $(0,0)$

For $x=1$

$y=2(1)=2$

The point is $(1,2)$

The answer in the attached figure

7 0

2 years ago

Read 2 more answers

Help pls, will mark brainliest

BaLLatris [955]

Here , we are provided with a table which shows 5 consecutive terms of an arithmetic sequence . But before solving further , let's recall that ;

The n'th term of a Arithmetic Sequence let's say it be ${\sf T_n}$ is given by ;

${\boxed{\bf T_{n}=T_{1}+(n-1)d}}$

Where , <u>d</u> is the common difference

Now , here we are given with ;

${\quad \qquad \sf \blacktriangleright \blacktriangleright \blacktriangleright T_{1}=8 \: and \: T_{5}=-4}$

We have to find the 2nd , 3rd and 4th term respectively ,

Now , by using the above formula , 5th term can be written as ;

${: \implies \quad \sf T_{1}+(5-1)d=T_{5}}$

Putting the values and transposing 1st term to RHS , we have ;

${: \implies \quad \sf 4d = -4-8}$

${: \implies \quad \sf d=-\dfrac{12}{4}}$

${: \implies \quad \sf d=-3}$

Now , as we got the common difference , so we can find out the missing terms now ;

${: \implies \quad \sf T_{2}= T_{1}+(2-1)d}$

${: \implies \quad \sf T_{2}= 8 +d}$

${: \implies \quad \sf T_{2}= 8-3}$

${: \implies \quad \bf \therefore \: T_{2}= 5}$

Now

${: \implies \quad \sf T_{3}= T_{1}+(3-1)d}$

${: \implies \quad \sf T_{3}= 8 +2d}$

${: \implies \quad \sf T_{3}= 8-6}$

${: \implies \quad \bf \therefore \: T_{3}= 2}$

Also ,

${: \implies \quad \sf T_{4}= T_{1}+(4-1)d}$

${: \implies \quad \sf T_{4}= 8 +3d}$

${: \implies \quad \sf T_{4}= 8-9}$

${: \implies \quad \bf \therefore \: T_{4}= -1}$

Now , The given table can be written as ;

${\begin{array}{|c|c|c|c|c|c|}\cline{1-6} \bf n & \sf 1 & 2 & 3 & 4 & 5 \\ \cline{1-6} \bf T_{n} & \sf 8 & 5 & 2 & -1 & -4 \end{array}}$

Note :- Kindly view the answer from web , if you're not able to see the full answer from here ;

brainly.com/question/26750175

8 0

2 years ago

G(x)=-x^2/4 +7<br> Over which interval does g have a negative average rate of change?

Sholpan [36]

Answer:

x = 49

Step-by-step explanation:

1- Substitute g ( x ) = 0

Reduce

g ( x ) = - x 2/4 + 7

2- Move the variable to the left

0 = - x 1/2 + 7

3- Simplify the equation

x 1/2 = 7

4- Simplify Evaluate

( x 1/2 ) ² = 7²

5- Check the solution

x= 49

6- Simplify

0= - 49 2/4 + 7

7- x = 49 is a solution

0 = 0

4 0

2 years ago

1 2/3 + (2 1/2) = ?<br> pls help

Sever21 [200]

The answer is about 4.1.

3 0

1 year ago

Read 2 more answers