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Answer:
2x³+3x²-8x+3
Step-by-step explanation:
So we know x=½,x=1 and x=-3
Then (2x-1)(x-1)(x+3) are the factors
(2x-1)[(x²+3x-x-3)]
(2x-1)[(x²+2x-3)]
2x³+4x²-6x-x²-2x+3
2x³+3x²-8x+3
slope =(y2-y1)/(x2-x1)
m=(-1-5)/(1--1)
m=-6/2
m=-3
y-y1=m(x-x1) point slope form
y-5 = -3 (x--1)
y-5 = -3 (x+1)
distribute
y-5 = -3x -3
add 5 to each side
y = -3x+2
Choice D
Answer:
I think you forgot to add the picture.