<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
4372/1000
Step-by-step explanation:
Answer:
Point (-5,21) would end up in quadrant II (2).
Step-by-step explanation:
It would end up in quadrant 2 because x=-5 which means it would go left.
y=21 which means it would go up.
Because of this, the point would end up in the top left of the graph which is quadrant 2.
1.= 1
2.= -15
3.= -18
4.= -1
5. = -11
6. = 22
Answer:
Jenna sold 280 boxes, Becca sold 105 boxes.
Step-by-step explanation:
For every 3 boxes B sold, J sold 8 boxes and ended with a total of 385 boxes sold.
3b+8j=385
From how the question is asked, we can assume that each round of sales would equal 11 total sales. (3b+8j=11)
Knowing the sales take place in intervals of 11, we can solve the problem by doing 385/11.
385/11=35
Finally, with 35 rounds of sales happening and knowing Jenna sells 8 while Becca sells 3 at each one, all that's left to do is multiply.
8x35=280
3x35=105
To be sure we can check our answer by adding them together, 280+105=385.