Answer : The volume of container will be 44.8 L
Explanation :
At STP condition,
The temperature and pressure are 273 K and 1 atm respectively.
As we know that at STP, 1 mole of substance occupies 22.4 L volume of gas.
As per question,
1 mole of nitrogen gas occupies 22.4 L volume
and,
1 mole of neon gas also occupies 22.4 L volume
Thus, total volume will be:
Total volume of container = 22.4 + 22.4 = 44.8 L
Hence, the volume of container will be 44.8 L
<h3>
<u>Answer:</u></h3>
<u>1 mole of a gas at STP occupies 22.4 L volume </u>
<u>Now the volume is given =78.4 therefore,</u>
<u>No. of moles of gas = 78.4 ÷ 22.4 = 3.5 moles</u>
<u>I hope it helps you~</u>
1) (Hvap)(moles of water)=236.9783574kJ
(40.67)(105/18.02)
2) (change in temperature)(mass)(Cliquid)=43.9345172kJ
(100)(105/18.02)(75.4)/1000
3) (Hfus)(moles of water)=35.01942286kJ
(6.01)(105/18.02)
4) (change in temperature)(mass)(Csolid)=3.181465039kJ
(15)(105/18.02)(36.4)/1000
Total released=319.1137625kJ
Answer:
1,45 mL
Explanation:
The Grignard reaction is a very important organometallic chemical reaction where the Grignard reagent ( alkyl, vinyl, or aryl-magnesium halides) acts as nucleophile in order to the formation of Carbon-Carbon bonds.
In the problem, the phenylmagnesium chloride is the grignard reagent. The volume of 2.0 M phenylmagnesium chloride solution you need to add 2.9 mmol is:
2,9 mmol × = <em>1,45 mL</em>
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I hope it helps!