Two trains leave towns 912 kilometers apart at the same time and travel toward each other. One train travels 12
1 answer:
Answer:
Step-by-step explanation:
Remark
The two trains are travelling towards each other. That means that their total distance = 912 km. Neither one has gone that distance by itself. The effect this has on the question is that you add the two rates multiplied by time.
Givens
r1 = x
r2 = x + 12
t = 3 hours
d = 912 km
Equation
d = r * t
r1 * t + r2 * t = 912
Solution
3x + 3*(x + 12) = 912 Remove the brackets
3x + 3x + 36 = 912 Combine like terms
6x + 36 = 912 Subtract 36 from both sides
<u> -36 -36</u>
6x = 876 Divide both sides by 6
6x/6 = 876/6
x = 146 km/h
Answer
Slow train = 146 km/hr
Fast train = 146 + 12 = 158 km/hr
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Answer:
2/19
Step-by-step explanation:
x+2 (9x) = 2
x+18x=2
19x=2
19x/19=2/19
2/19
Okay, are there any choices?
The answer would be A. 344000 and H=6 :)
You can make a proportion of 8/20 to 42/x and then simply cross multiply from there to solve for y