A.) (-2,-4)
(7+3)/2=5, (10+2)/2=6
(-7+5,-10+6)
(-2,-4)
b.)r^2=244
10^2+12^2=244
r=2(61)^(1/2)
c.)(x+2)^2+(y+4)^2=244
Answer:
Huh I am confused
Step-by-step explanation:
Do you need help with anything
<span>It must be the same as it was when constructing the arc above P.</span>
That number would be 6.
Since 5^2 = 25 and 6^2 = 36, we can see that the only possible whole number between sqrt(27) and sqrt(39) has to be 6.
Answer:
a, the following expression equals 13