An oxide of P contains 50% by mass of P. Its Relative molecular mass is 64. The molecular formula of the oxide is (P=32; O=16)
1 answer:
Answer:
B) PO2
Explanation:
first solve empirical formula
50%of P and 50%of O
- divide each by molecular mass
P. O
50/32. 50/16
1.5. 3.0
- divide both by the smallest
1.5/1.5. 3.0/1.5
1. :. 2
Empirical formula=PO2
Molecular formula=PO2
(PO2)n= 64
(32+(16×2)=64
(32+32)n=64
64n=64
n= 1
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