2 years ago

Sin thetha + cos thetha upon sec thetha + cosec thetha = sin thetha • cos thetha

Mathematics

1 answer:

Ludmilka [50]2 years ago

8 0

Answer:

steps below

Step-by-step explanation:

sin θ + cos θ / sec θ + cosec θ

= (sin θ + cos θ) / (1/cos θ+1/sin θ)

= (sin θ + cos θ) / ((sin θ + cos θ)/sin θ*cos θ)

= sin θ * cos θ

You might be interested in

Which statements are true according to the order of operations? Choose exactly two answers that are correct.

LiRa [457]

6 0

2 years ago

What is the solution to this equation? 4x^2+98=0

Bess [88]

There is no real solution

6 0

2 years ago

Can someone help me

gizmo_the_mogwai [7]

Answer:

its C just did it

Step-by-step explanation:

3 0

2 years ago

Given that F( x ) = x 2 + 2, evaluate F(1) + F(5).

stealth61 [152]

Hi there! :)

Answer:

$\huge\boxed{f(1) + f(5) = 30}$

Given:

$f(x) = x^{2} + 2$

Evaluate $f(1) + f(5)$

Solve for each:

$f(1) = (1)^{2} + 2 = 3$

$f(5) = (5)^{2} + 2 = 27$

$27 + 3 = 30$

3 0

2 years ago

Read 2 more answers

The typical full-time employee in a particular hotel works a 40-hour week. Last month, the hotel's 80 employees worked a total o

Mila [183]

Answer: There are 25 FTEs.

Step-by-step explanation:

Since we have given that

Number of hour week for full time employee = 40 hours

In a month we know that

Number of weeks = 4

Total number of hours in a month would be

$40\times 4\\\\=160\ hours$

If in last month, the hotel's 80 employees worked a total of 4000 hours,

So, Full time equivalent workers were employed by the hotel last month would be

$\dfrac{4000}{160}\\\\=25$

Hence, there are 25 FTEs.

7 0

2 years ago

Sin thetha + cos thetha upon sec thetha + cosec thetha = sin thetha • cos thetha​

Sin thetha + cos thetha upon sec thetha + cosec thetha = sin thetha • cos thetha