2*13= 26
2*16= 32
the answer is 2
Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
(x - 5)^2 + y^2 = 225/4,
or you could write it as (x - 5)^2 + y^2 = 56.25.
Step-by-step explanation:
The factor form is
(x - h)^2 + (y - k)^2 = r^2 where the center is (h, k) and r = the radius.
So we have:
(x - 5)^2 + (y - 0)^2 = r^2
As the point (-1, 9/2) is on the line:
(-1 - 5)^2 + (9/2)^2 = r^2
r^2 = 36 + 81/4
r^2 = 225/4.
So substituting for r^2:
(x - 5)^2 + (y - 0)^2 = 225/4
(x - 5)^2 + y^2 = 225/4 is the standard form.
The equation of the line passing through and is
. Here
is the slope of the line.
Substituting numerical values, the equation of the line is
The equation of the line is
16.445 I have no expectation sorry.