Given two points A(x₁,y₁) and B(x₂,y₂) the distance betwen these points will be:
dist(A,B)=√[(x₂-x₁)²+(y₂-y₁)²].
We have these points: A(0,0) and B(6,3); its distance will be:
dist(A,B)=√[(6-0)²+(3-0)²]
=√(6²+3²)
=√(36+9)
=√45 ≈ 6.71
Answer: D. 6.71 units.
The answer is C 16:20 because both numbers 4&5 are multiplied by four
Answer:
3/2 g.oogle if you want the explanation of your work.
Answer:
- Cos 45=6/x
x=6/cos 45=6√2
x=6√2
tan 45=y/6
y=tan45 ×6
y=6
2.
sin 60=y/10
y=sin60×10
y=5√3
again
Cos 60=x/10
x=½×10
x=5
3.
Sin 45=x/5
x=1/√2×5 or
x=5√2/2
again
y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]
4.
Sin 30=8/x
½×x=8
x=8*2
x=16
again
cos 30= y/x
√3/2×16=y
y=8√3
5.
sin 60=7/x
x=7/[√3/2]
x=14/√3 or 14√3/3
again
cos 60=y/x
½×14√3/3=y
7√3/2=y
y=7√3/2
<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u>
<u>S</u><u>i</u><u>n</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>p</u><u>e</u><u>r</u><u>p</u><u>e</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u>/</u><u>h</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u>e</u>
<u>C</u><u>o</u><u>s</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>b</u><u>a</u><u>s</u><u>e</u><u>/</u><u>h</u><u>y</u><u>p</u><u>o</u><u>t</u><u>e</u><u>n</u><u>u</u><u>s</u><u>e</u>
<u>T</u><u>a</u><u>n</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>=</u><u>p</u><u>e</u><u>r</u><u>p</u><u>e</u><u>n</u><u>d</u><u>i</u><u>c</u><u>u</u><u>l</u><u>a</u><u>r</u><u> </u><u>/</u><u>b</u><u>a</u><u>s</u><u>e</u>