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2 years ago

HELP PLEASE!!!!! PLEASE EXPLAIN WHEN GIVING THE ANSWER!!!! GIVING BRAINLIEST TO THE BEST EXPLANATION!!!!

Mathematics

2 answers:

atroni [7]2 years ago

4 0

Answer:Simplificando

5 (2j + 3 + j) = 0

Reordene os termos:

5 (3 + 2j + j) = 0

Combine termos semelhantes: 2j + j = 3j

5 (3 + 3j) = 0

(3 * 5 + 3j * 5) = 0

(15 + 15j) = 0

Resolvendo

15 + 15j = 0

a verdadeira questão é por que o vizinho de Sarah quer dentes de tubarão

Step-by-step explanation:

Mova todos os termos contendo j para a esquerda, todos os outros termos para a direita.

Adicione '-15' a cada lado da equação.

15 + -15 + 15j = 0 + -15

Combine termos semelhantes: 15 + -15 = 0

0 + 15j = 0 + -15

15j = 0 + -15

Combine termos semelhantes: 0 + -15 = -15

15j = -15

Divida cada lado por '15'.

j = -1

Simplificando

j = -1

Tubarão ou cação é um tipo de peixe de esqueleto cartilaginoso e um corpo hidrodinâmico (com exceção dos Squatiniformes, Hexanchiformes e Orectolobiformes)

SOVA2 [1]2 years ago

4 0

Maybe c just trust me

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Read 2 more answers

Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile

mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships is 135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC = 402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40' [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

$\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}$

Taking last two ratio,

$\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}$

Putting the value of BC , AC ,∠A,∠B

$\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}$

$\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}$

≈734.106 miles

Therefore they are 734.106 miles apart.

3 0

2 years ago