The reactants in the neutralization reaction are an acid and a base while the products are a salt and water.
Answer:
C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂
Explanation:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂
The above equation can be balance as illustrated below:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + HF + CoF₂
There are 16 atoms of H on the left side and 1 atom on the right side. It can be balance by writing 16 before HF as shown below:
C₇H₁₆ + CoF₃ —> C₇F₁₆ + 16HF + CoF₂
There are 3 atoms of F on the left side and a total of 34 atoms on the right side. It can be balance by writing 32 before CoF₃ and 32 before CoF₂ as shown below:
C₇H₁₆ + 32CoF₃ —> C₇F₁₆ + 16HF + 32CoF₂
Now, the equation is balanced.
Na₃PO₄ -----> 3Na(+) + PO₄(3-)
y-y.......................3y...........y
3y = 1.2
y = 0,4M
Na₃PO₄ -----> 3Na(+) + PO₄(3-)
0,4-0,4..............1,2..........0,4
0.........................1,2..........0,4
C = n/V
n = C×V
n = 0,4×0,65L
n = 0,26 mol Na₃PO₄
mNa₃PO₄: (23×3)+31+(16×4) = 164 g/mol
164g ----- 1 mol
Xg -------- 0,26 mol
X = 164×0,26
X = 42,64g Na₂SO₄
0.600
D) 0.600 is the final concentration of the solution of KCl.
V1 = 50.0 mL.
