Answer:
D) y=-4x+2
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-2-6)/(1-(-1))
m=-8/(1+1)
m=-8/2
m=-4
y-y1=m(x-x1)
y-6=-4(x-(-1))
y-6=-4(x+1)
y=-4x-4+6
y=-4x+2
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
<span>Absolute value of -98 is 98
Hope I helped:D </span>
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
3 shirts
