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2 years ago

15

Which element is found in period 3, group 2?

2 answers:

kicyunya [14]2 years ago

7 0

Answer:

Mg (Magnesium)

Explanation:

VladimirAG [237]2 years ago

6 0

Answer: Magnesium (Mg)

Explanation:

I attached a copy of a periodic table for reference.

When we look at the periodic table, go across to group 2 (Alkali Earth Metals) and then down to period 3, where we find Magnesium.

Interestingly, we could also gain this information from Magnesium's spdf electronic configuration: 1s²2s²2p⁶3s². With this, '3' tells us the period, and '²' tells the group.

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This is the third time I’m asking, please, On a wet road, is a higher coefficient of friction on the tires safer or a lower one

jenyasd209 [6]

Answer:

higher is safer

Explanation:

because it is a wet slippery surface, you would need more friction on the tires, to get more traction in the slippery wet road, if you had low friction you would not move anywhere and or could swerve off somewhere

4 0

7 months ago

The moon orbits Earth approximately once a month. <br><br> True<br><br> False

Zarrin [17]

Answer:true

Explanation:

It takes the moon approximately a month to complete an orbit round the earth

5 0

3 years ago

A vehicle of mass 100kg has a kinetic energy of 5000 J at an instant. The velocity at that instant is

snow_lady [41]

Answer:

$\bf\pink{10\:m/s}$

Explanation:

<h2><u>Given</u> :-</h2>

$\sf\red{Mass \ of \ vehicle \ (m) = 100 \ kg}$
$\sf\orange{Kinetic \ energy \ (K.E.) = 5000 \ J}$

<h2><u>To Find</u> :-</h2>

$\sf\green{Velocity\: of\: the \:vehicle \:at \:the \:instant}$

<h2><u>Formula to be used</u> :-</h2>

$\sf\blue{K.E. = \dfrac{1}{2} mv^{2}}$

Where,

K.E. = Kinetic energy possessed by the body
M = Mass of the body
V = Velocity of the body

<h2><u>Solution</u> :-</h2>

$\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}$

$\to\:\:\sf\orange{5000 = \dfrac{1}{2} \times 100 \times v^{2}}$

$\to\:\:\sf\green{5000 = 50 \times v^{2}}$

$\to\:\:\sf\blue{\dfrac{5000}{50} = v^{2}}$

$\to\:\:\sf\purple{100 = v^{2}}$

$\to\:\:\sf\red{\sqrt{100} = v}$

$\to\:\:\sf\orange{ 10 = v}$

$\to\:\:\bf\pink{v = 10\:m/s}$

Velocity of the vehicle at the instant is $\bf\green{10\:m/s}$

7 0

2 years ago

Read 2 more answers

a 1 m length of string is wrapped around a solid disk, of mass .25 kg and a radius of .30m, mounted on a frictionless axle. the

Nezavi [6.7K]

Answer:

60 rad/s

Explanation:

∑τ = Iα

Fr = Iα

For a solid disc, I = ½ mr².

Fr = ½ mr² α

α = 2F / (mr)

α = 2 (20 N) / (0.25 kg × 0.30 m)

α = 533.33 rad/s²

The arc length is 1 m, so the angle is:

s = rθ

1 m = 0.30 m θ

θ = 3.33 rad

Use constant acceleration equation to find ω.

ω² = ω₀² + 2αΔθ

ω² = (0 rad/s)² + 2 (533.33 rad/s²) (3.33 rad)

ω = 59.6 rad/s

Rounding to one significant figure, the angular velocity is 60 rad/s.

8 0

2 years ago

A car travels at a constant velocity of 40 m/s for 5.0 s, determine its displacement during this 5.0 s.

zimovet [89]

Answer:200 m

Explanation:

V=40m/s

T=5 s

Displacement=v*t

40*5=200

3 0

3 years ago