Could you build a triangle from each of the 3 lengths?

1 answer:

7 0

To form a triangle the sum of the two shorter sides must be greater than the longest side.
5, 5, 3 forms a triangle (isosceles)
8, 8, 8 forms a triangle (equilateral)
5, 6, 10 forms a triangle (obtuse angled scalene)

7, 8, 15 technically forms a triangle with an area of zero units. The vertices would be co-linear.
This will often be ignored as it has little practical use.

Fun fact. If you break a stick into 3 random lengths there is only a 25% chance they will be able to form a triangle.

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sergeinik [125]

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3, 3, 4, 4, 4, 5, 5, 5, 30

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8 0

2 years ago

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How do I solve this? I know it's easy but I don't understand clearly

faltersainse [42]

The answer is r = p/2n - x/n

8 0

1 year ago

How do you solve this ?

TEA [102]

$JK=9x-11\\KL=5x+2\\JL=(9x-11)+(5x+2)=(9x+5x)+(-11+2)=14x-9\\\\JK+KL=JL\\\\\text{substitute}\\\\14x-9=10x+7\ \ \ \ |+9\\\\14x=10x+16\ \ \ \ |-10x\\\\4x=16\ \ \ \ |:4\\\\x=4\\\\JK=9x-11\to JK=9(4)-11=36-11=25$