Percentage Weight-in-volume is defined as the <em><u>number of grams of a solute in a 100 ml (milliliters) solution.</u></em>
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<u>Percentage Weight-in-volume</u> can tell us about the <em>degree of concentration of a given solution.</em>
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The solute can be <em>crystalline or non-crystalline in nature.</em>
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The <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
- This question is based on a Percentage Weight-in-volume. The formula states that:
a% of a glucose solution =<u> a grams of glucose in a 100 mL solution</u>
Hence, 5% glucose solution = 5 grams of glucose / 100 mL solution
Therefore, the <u>number of grams of glucose</u> present in a <u>5% glucose solution</u> is 5 grams.
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Answer:
The resistance would be 64.10 ohms.
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0.0082 You have to equal out the amount of concentration with the unknown
Answer: A 59.5 degree celcius
The equation that we will use to solve this problem is :
PV = nRT where:
P is the pressure of gas = 1.8 atm
V is the volume of gas = 18.2 liters
n is the number of moles of gas = 1.2 moles
R is the gas constant = 0.0821
T is the temperature required (calculated in kelvin)
Using these values to substitute in the equation, we find that:
(1.8)(18.2) = (1.2)(0.0821)(T)
T = 332.5 degree kelvin
The last step is to convert the degree kelvin into degree celcius:
T = 332.5 - 273 = 59.5 degree celcius
Answer:
37.14 %
Explanation:
Using the equation, mass, M = D1 * V1
= D2 * V2
Where,
D1 = density of the liquid Nitrogen
D2 = density of gaseous Nitrogen
V1 = volume of the liquid Nitrogen
V2 = volume of the gaseous Nitrogen
Calculating V2,
0.808 * 185 = 1.15 * V2
Volume of Nitrogen after expansion = 129.98 m3.
Volume = L * b * h
= 10 * 10 * 3.5
Volume of the room = 350 m3.
Fraction of air = volume of Nitrogen after expansion/volume of the room * 100
= 129.98/350 *100
= 37.14 %
