Answer:
the thermistor temperature =
Explanation:
Given that:
A thermistor is placed in a 100 °C environment and its resistance measured as 20,000 Ω.
i.e Temperature
Resistance of the thermistor 20,000 ohms
Material constant = 3650
Resistance of the thermistor = 500 ohms
Using the equation :
Taking log of both sides
Replacing our values into the above equation :
Thus, the thermistor temperature =
Solution :
Speed of the air craft, = 262 m/s
Fuel burns at the rate of, = 3.92 kg/s
Rate at which the engine takes in air, = 85.9 kg/s
Speed of the exhaust gas that are ejected relative to the aircraft, =921 m/s
Therefore, the upward thrust of the jet engine is given by
F = 85.9(921 - 262) + (3.92 x 921)
= 4862635.79 + 3610.32
=
Therefore thrust of the jet engine is .
Answer: gravitational potential energy is converted into kinetic energy
Explanation:
When the diver stands on the platform, at 20 m above the surface of the water, he has some gravitational potential energy, which is given by
where m is the man's mass, g is the gravitational acceleration and h is the height above the water. As he jumps, the gravitational potential energy starts decreasing, because its height h above the water decreases, and he acquires kinetic energy, which is given by
where v is the speed of the diver, which is increasing. When he touches the water, all the initial gravitational potential energy has been converted into kinetic energy.