For a candle to burn, it requires a spark, which provides the activation energy for the oxidation reaction of the hydrocarbon making the candle.
It also requires oxygen to facilitate the oxidation of the hydrocarbon.
Therefore the two main requirements of combustion of a candle are oxygen and a spark (or an initial flame)
Answer:
Reduced, alkane
Explanation:
Wolf-Kishner reaction is a type of reduction reaction in which aldehydes and ketones are reduced to their corresponding alkane in the presence of a base.
This reaction occurs at high temperature.
Alkane formed has a same number of carbon as aldehyde and ketone.
If acetaldehyde undergoes a Wolf-Kishner reaction in the presence of base and heat, then ethane is formed. Nitrogen is formed as a byproduct.
Here, acetaldehyde is reduced to form ethane.
So, acetaldehyde undergoes a Wolf-Kishner reaction, which is the addition of hydrazine with subsequent addition of a base and heat. In this reaction, the aldehyde is reduced, resulting in alkane product.
This process is called meiosis! good luck!
1. Option A. Temperature and Salinity
2. Option D. (I think)
3. Option D.
Hope your test goes well!
Answer:
0.78 atm
Explanation:
Step 1:
Data obtained from the question. This includes:
Mass of CO2 = 5.6g
Volume (V) = 4L
Temperature (T) =300K
Pressure (P) =?
Step 2:
Determination of the number of mole of CO2.
This is illustrated below:
Mass of CO2 = 5.6g
Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol
Number of mole CO2 =?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 5.6/44
Number of mole of CO2 = 0.127 mole
Step 3:
Determination of the pressure in the container.
The pressure in the container can be obtained by applying the ideal gas equation as follow:
PV = nRT
The gas constant (R) = 0.082atm.L/Kmol
The number of mole (n) = 0.127 mole
P x 4 = 0.127 x 0.082 x 300
Divide both side by 4
P = (0.127 x 0.082 x 300) /4
P = 0.78 atm
Therefore, the pressure in the container is
