Answer:
A two-digit number can be written as:
a*10 + b*1
Where a and b are single-digit numbers, and a ≠ 0.
We know that:
"The sum of a two-digit number and the number obtained by interchanging the digits is 132."
then:
a*10 + b*1 + (b*10 + a*1) = 132
And we also know that the digits differ by 2.
then:
a = b + 2
or
a = b - 2
So let's solve this:
We start with the equation:
a*10 + b*1 + (b*10 + a*1) = 132
(a*10 + a) + (b*10 + b) = 132
a*11 + b*11 = 132
(a + b)*11 = 132
(a + b) = 132/11 = 12
Then:
a + b = 12
And remember that:
a = b + 2
or
a = b - 2
Then if we select the first one, we get:
a + b = 12
(b + 2) + b = 12
2*b + 2 = 12
2*b = 12 -2 = 10
b = 10/2 = 5
b = 5
then a = b + 2= 5 + 2 = 7
The number is 75.
And if we selected:
a = b - 2, we would get the number 57.
Both are valid solutions because we are changing the order of the digits, so is the same:
75 + 57
than
57 + 75.
You can calculate the distance between two point using this fomula:
√(x_2-x_1)^2+(y_2-y_1)^2
If you insert you values you get:
√(4-5)^2+(-7-2)^2 = 9.06 = 9.1
Answer: 36
Step-by-step explanation:
(Triangle ABC is isosceles)
(base angles of an isosceles triangle are congruent)
(In triangle CMB, angles in a triangle add to 180 degrees)
(triangle sum theorem)
(30-60-90 triangle CMB)
(sides opposite congruent angles in a triangle are congruent)
(segment addition postulate)
It’s cheaper to take this bus. Compare 166 to 190
