21 picks
altogether (2x+5x)=21
7x=21
x=3
2*3=6 orange picks
or
x=orange, y = greens
x+y=21
x/y=2/5,----> y=5x/2
x+5x/2=21
2x/2+5x/2=21
7x/2=21
7x=42,
x=6 orange picks
Answer:
The probability is
Step-by-step explanation:
If she has n distinct password candidates and only one of which will successfully log her into a secure system, the probability that her first first successful login will be on her k-th try is:
If k=1
Because, in her first try she has n possibles options and just one give her a successful login.
If k=2
Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and 1 of that give her a successful login.
If k=3
Because, in her first try she has n possibles options and n-1 that are not correct, then, she has n-1 possibles options and n-2 that are not correct and after that, she has n-2 possibles options and 1 give her a successful login.
Finally, no matter what is the value of k, the probability that her first successful login will be (exactly) on her k-th try is 1/n
6(2k-3) is the answer to this problem.
make a distributive
take the 6 out of the equation and u have remaining 2k-3. 6(2k-3)
Answer:
x∈{-7√2, 7√2}
Step-by-step explanation: