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1 year ago

Evaluate the expression if m = – 4, n = 1, p = 2, q = –6, r = 5, and t = -2. |3r + 6m

Mathematics

1 answer:

fgiga [73]1 year ago

8 0

Answer:

m=4,2=9, and r=. (Examples 1-6). 1. 3+ m 7. 2. z-m 5. | 3. 12r 2

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Follow the steps to finish solving the equation -3x+18=7x

Svet_ta [14]

Answer:

x = 1.8

Step-by-step explanation:

We have the equation -3x + 18 = 7x. First we do your step 1, and get: 18 = 10x. When doing your step 2, we divide both sides by 10 to isolate x alone. 18/10 = 1.8. X = 1.8

6 0

2 years ago

Given f(x) = 18x + 8, find x when f(x)= 14.

Naddika [18.5K]

The answer is 0.3 (1/3.)

Proof?

f(0.3) = 18(0.3) + 8

f(0.3) = 6 + 8

f(0.3) = 14

14 = 14

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2 years ago

3 decreased by the difference of h and 5

sergejj [24]

Is there a picture that goes with this problem?

8 0

11 months ago

Use trig to find the legs of ABC if the base is AC and the height is BC (round to nearest tenth)

umka2103 [35]

Answer:

GIVEN :-

∠A = 15°
Length of AB (hypotenuse) = 60 ft

TO FIND :-

Length of BC
Length of AC
Area of ΔABC

FACTS TO KNOW BEFORE SOLVING :-

$\sin \theta = \frac{Side \: opposite \: to \: \theta}{Hypotenuse}$
$\cos \theta = \frac{Side \: adjacent \: to \: \theta}{Hypotenuse}$

SOLUTION :-

In ΔABC ,

$\sin 15 = \frac{BC}{60}$

$=> 0.2588... = \frac{BC}{60}$

$=> BC = (0.2588....) \times 60 = 15.5291.....$ ≈ 15.5 ft

$\cos 15 = \frac{AC}{60}$

$=> 0.9659..... = \frac{AC}{60}$

$=> AC = (0.9659.....) \times 60 = 57.9555.....$ ≈ 58 ft

Area of ΔABC = $\frac{1}{2} \times 58 \times 15.5 = 449.5 \:ft^2$

4 0

2 years ago

Help!! Any effort is very much appreciated

Tanya [424]

Answer:

-2

Step-by-step explanation:

Gradient/slope = $\frac{-1-19}{16-6} = \frac{-20}{10} = -2$

3 0

2 years ago