Answer:
1 3/7 quarts should be drained off and replaced with pure antifreeze.
1 3/7 ≈ 1.4286
Current amount of antifreeze in quarts is -
30/ 100 × 10 = 3
40% ---> 4 quarts
Let the amount drained of and replaced with antifreeze be x-
The amount left after draining off is 10 − x.
The amount of antifreeze is 30/ 100 (10−x).
30/100(10-x)+x=4
3-3/10x+x=4
3+x(1-3/10)=4
x=1*10/7=1 3/7 quarts
check;
10- 1 3/7 = 8 4/7
=(30/100*8 4/7)+1 3/7
=(3/10 * 60/7) + 10/7
=3*6/7 + 10/7
=28/7
=4
4 liters of pure antifreeze is mixed into 10 quarts.
X+5+2x-2+90=180. combine like terms and solve like a normal algebra problem to find x. if you need to find the answer for a certain angle, plug in the value you got for x into one of the angle equations
X= -15
First, we want to combine like terms.
4x-10=20+6x
Subtract 4x from both sides
-10=20+2x
Subtract 20 from both sides
-30=2x
Divide by 2 to isolate the variable
X= -15
Answer:
Explanation:
The equation is:
The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.
This means that we can solve separately for the two terms:
Solving the first equation:
Solving the second equation: