What is the square root of -1?
2 answers:
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Answer:
Hence Nell's mom Chocolate milk is more Chocolaty.
Step-by-step explanation:
Given:
Chocolate syrup used by Nell's mom = 30 ml
Amount of milk used = 2 ounces.
We will first find Amount of chocolate syrup used in 1 ounce of milk.
Now In 2 ounces of milk = 30 ml of chocolate syrup.
So in 1 ounce of milk = Amount of Chocolate syrup used for 1 ounce milk.
By using Unitary method we get;
Amount of Chocolate syrup used for 1 ounce milk=
Hence For every 1 ounce of milk Nell's mom uses 15 ml of chocolate syrup.
Also Given:
Chocolate syrup used by Nell's dad = 65 ml
Amount of milk used = 5 ounces.
We will first find Amount of chocolate syrup used in 1 ounce of milk.
Now In 5 ounces of milk = 65 ml of chocolate syrup.
So in 1 ounce of milk = Amount of Chocolate syrup used for 1 ounce milk.
By using Unitary method we get;
Amount of Chocolate syrup used for 1 ounce milk=
Hence For every 1 ounce of milk Nell's dad uses 13 ml of chocolate syrup.
Since The amount of chocolate syrup used by Nell's mom is more than Nell's dad.
Hence Nell's mom Chocolate milk is more Chocolaty.
Problem 5
<h3>Answer: 6i</h3>------------------
Explanation:
We have these four identities
- i^0 = 1
- i^1 = i
- i^2 = -1
- i^3 = -i
Notice how computing i^4 leads us back to 1. So i^4 = i^0. The pattern repeats every 4 terms. So we divide the exponent by 4 and look at the remainder. We ignore the quotient entirely. We can see that 28/4 = 7 remainder 0. Meaning that i^28 = i^0 = 1.
We can think of it like this if you wanted
i^28 = (i^4)^7 = 1^7 = 1
Then the sqrt(-36) becomes 6i
So overall, we end up with the final answer of 6i
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Problem 6
<h3>Answer: -3i</h3>------------------
Explanation:
We'll use the ideas mentioned in problem 5
46/4 = 11 remainder 2
i^46 = i^2 = -1
sqrt(-9) = 3i
The two outside negative signs cancel out, but there's still a negative from -1 we found earlier. So we end up with -3i
In other words, here is one way you could write out the steps
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Problem 7
<h3>Answer: -1</h3>------------------
Work Shown:
i^10 = i^2 because 10/4 = 2 remainder 2
i^19 = i^3 because 19/4 = 4 remainder 3
i^7 = i^3 because 7/4 = 1 remainder 3
Again, all we care about are the remainders.
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Problem 8
<h3>Answer: -1 + i</h3>------------------
Work Shown:
i^22*i^6 = i^(22+6) = i^28
Earlier in problem 5, we found that i^28 = i^0 = 1
So,