Answer:
d=2r= 2·24=48ft
Step-by-step explanation:
The function is
f(x) = (1/3)x² + 10x + 8
Write the function in standard form for a parabola.
f(x) = (1/3)[x² + 30x] + 8
= (1/3)[ (x+15)²- 225] + 8
= (1/3)(x+15)² -75 + 8
f(x) = (1/3)(x+15)² - 67
This is a parabola with vertex at (-15, -67).
The axis of symmetry is x = -15
The curve opens upward because the coefficient of x² is positive.
As x -> - ∞, f -> +∞.
As x -> +∞, f -> +∞
The domain is all real values of x (see the graph below).
Answer: The domain is (-∞, ∞)
The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...
The mean is centered among the other numbers in both sets of data.
_____
The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.
Answer:
This is the answer of your question.
<h3>
Answer: -10</h3>
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Work Shown:
First we need to evaluate f(3)
f(x) = -x^2 + 2x
f(x) = -(x)^2 + 2(x)
f(3) = -(3)^2 + 2(3) ... replace every x with 3; apply PEMDAS to simplify
f(3) = -9 + 6
f(3) = -3
Then we subtract 7 from both sides
f(3) - 7 = -3 - 7
f(3) - 7 = -10