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2 years ago

13

How to write 15,409 in word form

2 answers:

Papessa [141]2 years ago

5 0

Fifteen thousand, four hundred and nine

Furkat [3]2 years ago

5 0

Fifteen thousand, four hundred and nine

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Describe the main parts of a proof

uysha [10]

Show how you got your answer in reverse. For example... if ur question is
4+4/(?)=4
8/?=4
oh its commen sense that the answer is 2.
now show how u got the answer 2.

? is 2 because, 4 times 2 equals 8
4(2)=8

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2 years ago

Write any equation in slope intercept form of the line that passes through the given point and it's parallel to the graph of the

Orlov [11]

Paralalell means that is has the same slope
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2 years ago

A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

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2 years ago

Chris made his aunt a garden. The width is 7 2/5 ft and the length is 5 1/2 ft. What is the area of the garden?

pishuonlain [190]

Answer:

Hello! if Chris garden is a square shape then the answer is 40 7/10 in fraction form or 40.7 in decimal form

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1 year ago

A circular swimming pool is 21 feet in diameter. What is the circumstances of the swimming pool?

Reptile [31]

Hello there!

21 * 3.14 = 65.94

Thus,

The circumstances of the swimming pool is 65.94

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2 years ago