Answer:
The price of the admission is 15.
Step-by-step explanation:
From the information given, you can write the following equations:
a+3e=45 (1)
a+5e=65 (2), where:
a is the admission cost
e is the exhibition cost
First, you can solve for a in (1):
a=45-3e (3)
Second, you can replace (3) in (2):
45-3e+5e=65
45+2e=65
2e=65-45
2e=20
e=20/2
e=10
Finally, you can replace the value of e in (3):
a=45-3e
a=45-3(10)
a=45-30
a=15
According to this, the price of the admission is 15.
Answer:
18
Step-by-step explanation:
Answer:
Consider the parent logarithm function f(x) = log(x)
Now,
Let us make transformations in the function f(x) to get the function g(x)
•On streching the graph of f(x) = log(x) , vertically by a factor of 3, the graph of y = 3log(x) is obtained.
•Now, shrinking the graph of y = 3log(x) horizontally by a fctor of 2 to get the grpah of y = 3log(x/2) i.e the graph of g(x)
Hence, the function g(x) after the parent function f(x) = log(x) undergoes a vertical stretch by a factor of 3, and a horizontal shrink by a factor of 2 is
g(x) = 3 log(x/2) (Option-B).
Answer with explanation:
The equation which we have to solve by Newton-Raphson Method is,
f(x)=log (3 x) +5 x²
Initial Guess =0.5
Formula to find Iteration by Newton-Raphson method
So, root of the equation =0.205 (Approx)
Approximate relative error
Approximate relative error in terms of Percentage
=0.41 × 100
= 41 %
True,
4a - 3b
4(6) - 3(1)
24 - 3 = 21